ExampleDebug.cpp

Demonstrates the usage of debug levels.

The new concept avoids multiple definitions of debug levels.

Example:

file baseclass.hh #define DL_BASE 0x1 class baseclass { foo() { BIASCDOUT(DL_BASE, "output of base class");} }; file subclass.hh #include "baseclass.hh" #define DL_SUB 0x1 class subclass : public baseclass { foo2() { foo(); BIASCDOUT(DL_SUB, "output of subclass"); } };

Now calling

subclass sc; sc.SetDebugLevel(DL_SUB); sc.foo2();

results in the unexpected debug output "output of base class".

To avoid this use the new debug level concept presented here.

Author

woelk 09/2006

/* 
This file is part of the BIAS library (Basic ImageAlgorithmS).

Copyright (C) 2003-2009    (see file CONTACT for details)
  Multimediale Systeme der Informationsverarbeitung
  Institut fuer Informatik
  Christian-Albrechts-Universitaet Kiel


BIAS is free software; you can redistribute it and/or modify
it under the terms of the GNU Lesser General Public License as published by
the Free Software Foundation; either version 2.1 of the License, or
(at your option) any later version.

BIAS is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
GNU Lesser General Public License for more details.

You should have received a copy of the GNU Lesser General Public License
along with BIAS; if not, write to the Free Software
Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA  02111-1307  USA
*/

/** @example ExampleDebug.cpp
    @relates Debug
    @brief Demonstrates the usage of debug levels.
    
    The new concept avoids multiple definitions of debug levels.

    Example:

    // file baseclass.hh
    #define DL_BASE 0x1
    class baseclass {
      foo() { BIASCDOUT(DL_BASE, "output of base class");}
    };
    // file subclass.hh
    #include "baseclass.hh"
    #define DL_SUB 0x1
    class subclass : public baseclass
    {
      foo2() { foo(); BIASCDOUT(DL_SUB, "output of subclass"); }
    };
      
    Now calling

    subclass sc;
    sc.SetDebugLevel(DL_SUB);
    sc.foo2();
    
    results in the unexpected debug output "output of base class".

    To avoid this use the new debug level concept presented here.
    @ingroup g_examples
    @author woelk 09/2006
*/

#include <Base/Debug/Debug.hh>

using namespace BIAS;
using namespace std;

/** \cond HIDDEN_SYMBOLS*/
class MyDebugClass : public Debug
{
public:

  MyDebugClass() : myInt(0) 
  {
    // tell the class abouts its debug levels
    NewDebugLevel("DL1");
    NewDebugLevel("DL2");
  }

  inline ~MyDebugClass() {}

  void foo(int arg) {
    // use new debug output macro 
    BCDOUT(DL1, "MyDebugClass::foo() : arg = " << arg << endl);
    myInt += arg;
    BCDOUT(DL2, "MyDebugClass::foo() : myInt = " << myInt << endl);
  }

protected:

  int myInt; // some internal variable

};

/** \endcond */

int main(int argc, char *argv[])
{
  MyDebugClass mc; 
  cout << "Show me the available debug levels: " << endl;
  mc.ShowDebugLevel();
  cout << "Without debug output: " << endl;
  mc.foo(5);
  cout << "With debuglevel \"DL1\": " << endl;
  mc.AddDebugLevel("DL1");
  mc.foo(7);
  cout << "With debuglevel \"DL1\" and \"DL2\": " << endl;
  mc.AddDebugLevel("DL2");
  mc.foo(-42);
  cout << "Again without debug output: " << endl;
  mc.SetDebugLevel(0);
  mc.foo(666);
  cout << "With debuglevel \"DL2\": " << endl;
  mc.AddDebugLevel("DL2");
  mc.foo(-42);
  cout << "Print current debug level: " << endl;
  mc.PrintDebugLevel();
  return 0;
}